Message in Russian (Русский)

Пользовательский метод оператора "<var>Method name</var>" для оператора "<var>X</var>" должен возвращать такой же тип, как и его параметр, или производный тип.

Unlocalized message

The user-defined operator method '<var>Method name</var>' for operator '<var>X</var>' must return the same type as its parameter or a derived type.

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